31p+6p^2=-5

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Solution for 31p+6p^2=-5 equation:



31p+6p^2=-5
We move all terms to the left:
31p+6p^2-(-5)=0
We add all the numbers together, and all the variables
6p^2+31p+5=0
a = 6; b = 31; c = +5;
Δ = b2-4ac
Δ = 312-4·6·5
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-29}{2*6}=\frac{-60}{12} =-5 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+29}{2*6}=\frac{-2}{12} =-1/6 $

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